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Annanian
@Annanian
August 2022
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какой объем метана можно получить с 20 кг карбида алюминия (Al4C3)?
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Potassium
Al4C3 + 12HCl = 4AlCl3 + 3CH4
20/144 = x/67.2
x = (20*67.2)/144 = 9.333 л
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Answers & Comments
20/144 = x/67.2
x = (20*67.2)/144 = 9.333 л