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Ketty0987
@Ketty0987
July 2022
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Какой объем оксида углерода(4)(н.у.) и какая масса воды образуются при сгорании 580 г бутана C4H10?
Схема реакции:C4H10+O2---->CO+H2O
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AlexMiner
1)n(C4H10)=580/58=10 моль
2)V(co2)=10*22.4=224 л
3)m(H20)=10*18=180 г
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Answers & Comments
2)V(co2)=10*22.4=224 л
3)m(H20)=10*18=180 г