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greenandclear
@greenandclear
August 2022
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какой обЪем углекислого газа можно получить сжигая из 2 л ацетилена и 12 л этана??
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dubes
2C2H2+5O2=4CO2+2H2O
n(C2H2)=2/22,4=0,089 моль
n(C2H2)/2=n(CO2)/4
n(CO2)=0,178 моль
V(CO2)=0,178*22,4=3,9872 л
2С2H6+7O2=4CO2+6H2O
n(C2H6)=12/22,4=0,54 моль
n(C2H6)/2=n(CO2)/4
n(CO2)=1,08 моль
V(CO2)=1,08*22,4=24,192 л
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Answers & Comments
n(C2H2)=2/22,4=0,089 моль
n(C2H2)/2=n(CO2)/4
n(CO2)=0,178 моль
V(CO2)=0,178*22,4=3,9872 л
2С2H6+7O2=4CO2+6H2O
n(C2H6)=12/22,4=0,54 моль
n(C2H6)/2=n(CO2)/4
n(CO2)=1,08 моль
V(CO2)=1,08*22,4=24,192 л