Zn+2HCl=ZnCl2+H2
m(HCl)=36.5*0.1=3.65 г
кол-во(HCl)=3.65:36.5=0.1 моль
кол-во(ZnCl2) =0.1:2=0.05 моль=кол-во(Н2)
m(ZnCl2)=0.05*136=6.8 г
V(H2)=0.05*22.4=1.12 л
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Zn+2HCl=ZnCl2+H2
m(HCl)=36.5*0.1=3.65 г
кол-во(HCl)=3.65:36.5=0.1 моль
кол-во(ZnCl2) =0.1:2=0.05 моль=кол-во(Н2)
m(ZnCl2)=0.05*136=6.8 г
V(H2)=0.05*22.4=1.12 л