2C2H5OH + 2Na = 2C2H5ONa + H2
9.2/46 = x/22.4
x = 4.48 л — теоретически.
ŋ(H2)= 90% ==>
ŋ(практ.)= (4.48 * 0.9)= 4.032 л
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2C2H5OH + 2Na = 2C2H5ONa + H2
9.2/46 = x/22.4
x = 4.48 л — теоретически.
ŋ(H2)= 90% ==>
ŋ(практ.)= (4.48 * 0.9)= 4.032 л