M(HCl) = 35+1 = 36 г/моль
n(HCl) = m(HCl)/M(HCL) = 14.6/36 = 0.41 моль
V = 0.41х22,4 = 9,184 л
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M(HCl) = 35+1 = 36 г/моль
n(HCl) = m(HCl)/M(HCL) = 14.6/36 = 0.41 моль
V = 0.41х22,4 = 9,184 л