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AllisonHarvard
@AllisonHarvard
July 2022
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Какой объём кислорода необходим для сжигания 5 литров С6H16?
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andreevachepurn
C6H16+10O2= 6CO2+8H2O
V(o)=5*10*22.4/22.4= 50л
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Answers & Comments
V(o)=5*10*22.4/22.4= 50л