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Newtone
@Newtone
August 2021
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Какой объём кислорода потребуется для сгорания 400л. метана?
(Ответ нужен с решением)
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nikita7587
Verified answer
CH4+2O2=CO2+2H2O
n(CH4)=400л/22.4=17.86 моль
n(O2)=2n(CH4)=35.72 моль
V(O2)=35.72моль*22,4=800,13~800 литров
2 votes
Thanks 3
Stannum
Verified answer
400--------x=800 л
CH4 + 2O2 = CO2 + 2H2O
22,4----44,8 л
или 1 к 2
0 votes
Thanks 0
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Answers & Comments
Verified answer
CH4+2O2=CO2+2H2On(CH4)=400л/22.4=17.86 моль
n(O2)=2n(CH4)=35.72 моль
V(O2)=35.72моль*22,4=800,13~800 литров
Verified answer
400--------x=800 лCH4 + 2O2 = CO2 + 2H2O
22,4----44,8 л
или 1 к 2