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dashalisicika
@dashalisicika
July 2022
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Какой объём н.у занимают 3,01*10 в 23 степени молекул азота
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Миранда99
N(N2)= N/Na
n(N2)= 3.01*10в23 * 6,02*10в23=0,5 моль
V(N2)=n*Vm
V(N2)=0.5*22.4=11.2 дм3
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Answers & Comments
n(N2)= 3.01*10в23 * 6,02*10в23=0,5 моль
V(N2)=n*Vm
V(N2)=0.5*22.4=11.2 дм3