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valentingrukalo
@valentingrukalo
July 2022
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Какой объём O2 образуется при разложении 3.6 г воды
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2H2O=2H2+O2
n(H2O)=m/M=3.6/(2+16)=3.6/18=0.2 моль
n(O2)=1/2n(H2O)=0.2/2=0.1 моль
V(O2)=n*Vm=0.1*22.4=2.24 л
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valentingrukalo
Можно дано
cfx
Дано:
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m(H2O)=3.6 г
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V(O2)=?
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Answers & Comments
n(H2O)=m/M=3.6/(2+16)=3.6/18=0.2 моль
n(O2)=1/2n(H2O)=0.2/2=0.1 моль
V(O2)=n*Vm=0.1*22.4=2.24 л