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kekekekekekekkekek
@kekekekekekekkekek
August 2021
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Какой объём оксида фосфора 5 образуется при взаимодействии 76 г оксида фосфора 3 с кислородом????????????!!!
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omirov32
P2O3+O2=P2O5
n(p2o3)=76/110=0,7 моль
m(p2o5)=0,7•142=99,4г
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Answers & Comments
n(p2o3)=76/110=0,7 моль
m(p2o5)=0,7•142=99,4г