m(CH3-CH(CH3)-CH2-CH2-CH3) = 280 g

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V(CO2)-?

2CH3-CH(CH3)-CH2-CH2-CH3 + 19O2-->12CO2+14H2O

M(CH3-CH(CH3)-CH2-CH2-CH3) = 86 g/mol

n(CH3-CH(CH3)-CH2-CH2-CH3) = m/M = 280 / 86 = 3.26 mol

2n(CH3-CH(CH3)-CH2-CH2-CH3) =12n(СO2)

n(O2) =  12*3.26 / 2 = 19.56 mol

V(O2) = n*Vm = 19.56 * 22.4 = 438.144 L

ответ 438.144 L