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AHAH4C228
@AHAH4C228
July 2022
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Какой объём займут 9*10²³ молекул неона.
С формулами
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svin99
N = N/Na = 9*10^23/6*10^23 = 1,5 моль.
V = n*Vm = 1.5*22.4 = 33.6 л
3 votes
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Answers & Comments
V = n*Vm = 1.5*22.4 = 33.6 л