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shevcovaa2001
@shevcovaa2001
June 2022
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какой объём займут при нормальных условиях 3 г водорода?
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svetka1574
Verified answer
Дано:
m(H2)=3г
М(Н2) = 2 г/моль
Vm=22,4 л/моль
Найти:
V(H2)
n(H2) = m(H2) / M(H2) = 3 / 2 = 1,5 моль
V(H2) = Vm * n(H2) = 22,4 * 1,5 = 33,6 л
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Answers & Comments
Verified answer
Дано:m(H2)=3г
М(Н2) = 2 г/моль
Vm=22,4 л/моль
Найти:
V(H2)
n(H2) = m(H2) / M(H2) = 3 / 2 = 1,5 моль
V(H2) = Vm * n(H2) = 22,4 * 1,5 = 33,6 л