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Iraeuroset3
@Iraeuroset3
November 2021
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Какой объём занимает 28г азота(N2)
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Alenall
M(N2) = 14 • 2 = 28 г/моль
n(N2) = 28 г : 28 г/моль = 1 моль
V(N2) = 22,4 л/моль • 1 моль = 22,4 л
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Answers & Comments
n(N2) = 28 г : 28 г/моль = 1 моль
V(N2) = 22,4 л/моль • 1 моль = 22,4 л