November 2021 0 16 Report
Какой вариант? Решения не надо. Даны вершины треугольника A(−2,1),B(3,3),С(1,0). Найти длину стороны АВ а) 2х-5у+9=0
в)2х+5у+9=0
с) 2х-5у+1=0
d) 2x-5y+9=1
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