дано
W(Fe2O3) = 80%
η(Fe) = 0.9
mтехн(Fe2O3) = 1 kg = 1000 g
---------------------
m(Fe)-?
m чист (Fe2O3) = 1000 * 80% / 100% = 800 g
Fe2O3+3CO-->2Fe+3CO2
M(Fe2O3) = 160 g/mol
n(Fe2O3) = m/M = 800/ 160 = 5 mol
n(Fe2O3) = 3n(Fe)
n(Fe) = 3*5 = 15 mol
M(Fe) = 56 g/mol
mтеор (Fe) = n*M = 15*56 = 840 g
m(практ Fe) = 840 * 0.9= 756 g
ответ 756 г
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Verified answer
дано
W(Fe2O3) = 80%
η(Fe) = 0.9
mтехн(Fe2O3) = 1 kg = 1000 g
---------------------
m(Fe)-?
m чист (Fe2O3) = 1000 * 80% / 100% = 800 g
Fe2O3+3CO-->2Fe+3CO2
M(Fe2O3) = 160 g/mol
n(Fe2O3) = m/M = 800/ 160 = 5 mol
n(Fe2O3) = 3n(Fe)
n(Fe) = 3*5 = 15 mol
M(Fe) = 56 g/mol
mтеор (Fe) = n*M = 15*56 = 840 g
m(практ Fe) = 840 * 0.9= 756 g
ответ 756 г