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polina20002000
@polina20002000
March 2022
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Какова средняя квадратичная скорость молекул гелия при 27 С?
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sirorion
Verified answer
T=27+273=300 K, M=4*10^-3 кг/моль, Na=6*10^23, k=1.38*10^-23; V=?
m0=M/Na=4*10^-3/6*10^23=6.7*10^-27 кг
м/c.
0 votes
Thanks 1
koliaver
Verified answer
T=t+273=300 К; V=(3RT/M)^1/2; V= (3*8.31*300/4*10^-3)^1/2=1367(м/с)
Ответ:1367 м/с.
2 votes
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Answers & Comments
Verified answer
T=27+273=300 K, M=4*10^-3 кг/моль, Na=6*10^23, k=1.38*10^-23; V=?m0=M/Na=4*10^-3/6*10^23=6.7*10^-27 кг
м/c.
Verified answer
T=t+273=300 К; V=(3RT/M)^1/2; V= (3*8.31*300/4*10^-3)^1/2=1367(м/с)Ответ:1367 м/с.