Какую формулу можно применить?
16u^2 – 8u(3u+1) + (3u + 1)
✓a^2- 2ab+b^2= (a - b)^2
✓(а - b)(a+b) = a^2 - b^2
✓(a - b)(a^2 +ab+b^2) = a^3 - b^3
16u^2 – 8u(3u+1) + (3u + 1)
✓a^2- 2ab+b^2= (a - b)^2
✓(а - b)(a+b) = a^2 - b^2
✓(a - b)(a^2 +ab+b^2) = a^3 - b^3
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Ответ:
Объяснение:
16u^2 – 8u(3u+1) + (3u + 1)^2
a^2- 2ab+b^2= (a - b)^2
16u^2 – 8u(3u+1) + (3u + 1)^2= (4u-3u-1)²= (u-1)²