Ответ:
дано
m ppa(HNO3) = 30 g
W(HNO3) = 90%
V(C2H2) = 13.44 L
--------------------
m(C6H5NO2) - ?
3C2H2-->C6H6
C6H6+HNO3-->C6H5NO2+H2O
n(C2H2) = V(C2H2) / Vm = 13.44 / 22.4 = 0.6 mol
3n(C2H2) = n(C6H6)
n(C6H6) = 0.6 / 3 = 0.2 mol
m(HNO3) = m(ppa HNO3) * W(HNO3) / 100% = 30*90% / 100% = 27 g
M(HNO3) = 63 g/mol
n(HNO3) = m/M = 27 / 63 = 0.43 mol
n(C6H6) < n(HNO3) бензол в недостатке
n(C6H6) = n(C6H5NO2) = 0.2 mol
M(C6H5NO2) = 123 g/mol
m(C6H5NO2) = n*M = 0.2*123 = 24.6 g
ответ 24.6 г
Объяснение:
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Ответ:
дано
m ppa(HNO3) = 30 g
W(HNO3) = 90%
V(C2H2) = 13.44 L
--------------------
m(C6H5NO2) - ?
3C2H2-->C6H6
C6H6+HNO3-->C6H5NO2+H2O
n(C2H2) = V(C2H2) / Vm = 13.44 / 22.4 = 0.6 mol
3n(C2H2) = n(C6H6)
n(C6H6) = 0.6 / 3 = 0.2 mol
m(HNO3) = m(ppa HNO3) * W(HNO3) / 100% = 30*90% / 100% = 27 g
M(HNO3) = 63 g/mol
n(HNO3) = m/M = 27 / 63 = 0.43 mol
n(C6H6) < n(HNO3) бензол в недостатке
n(C6H6) = n(C6H5NO2) = 0.2 mol
M(C6H5NO2) = 123 g/mol
m(C6H5NO2) = n*M = 0.2*123 = 24.6 g
ответ 24.6 г
Объяснение: