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olgasavko98
@olgasavko98
July 2022
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Какую массу оксида натрия надо растворить в 1014г раствора, содержащего 240г NaOH,чтобы получить раствор с w(NaOH)=40%
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9856565651
Na2O + H2O = 2NaOH
2*NaOH/Na2O = 1.29
(240+1.29X)/(1014+X) = 0.4
240+1.29X = 405.6 + 0.4X
0.89X = 165.6
X=186 г Na2O
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Answers & Comments
2*NaOH/Na2O = 1.29
(240+1.29X)/(1014+X) = 0.4
240+1.29X = 405.6 + 0.4X
0.89X = 165.6
X=186 г Na2O