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kykyma
@kykyma
July 2022
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Какую массу ортофосфорной кислоты можно получить при нагревании 0,2 моль оксида фосфора (V) с достаточным количеством воды
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dec77cat
P₂O₅ + 3H₂O = 2H₃PO₄
M(H₃PO₄)=98 г/моль
n(P₂O₅)=0,2 моль
n(H₃PO₄)=2n(P₂O₅)
m(H₃PO₄)=M(H₃PO₄)n(H₃PO₄)=2M(H₃PO₄)n(P₂O₅)
m(H₃PO₄)=2*98*0,2=
39,2 г
1 votes
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Answers & Comments
M(H₃PO₄)=98 г/моль
n(P₂O₅)=0,2 моль
n(H₃PO₄)=2n(P₂O₅)
m(H₃PO₄)=M(H₃PO₄)n(H₃PO₄)=2M(H₃PO₄)n(P₂O₅)
m(H₃PO₄)=2*98*0,2=39,2 г