Ответ:
дано
n(CH3CH2COOH) = 1.4 mol
+K2O
-----------------------
m(CH3CH2COOK) - ?
2CH3CH2COOH+K2O-->2CH3CH2COOK+H2O
2n(CH3CH2COOH) = 2n(CH3CH2COOK) =1.4 mol
M(CH3CH2COOK) = 112 g/mol
m(CH3CH2COOK) = n*M = 1.4 * 112 = 156.8 g
ответ 156.8 гр
Объяснение:
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Verified answer
Ответ:
дано
n(CH3CH2COOH) = 1.4 mol
+K2O
-----------------------
m(CH3CH2COOK) - ?
2CH3CH2COOH+K2O-->2CH3CH2COOK+H2O
2n(CH3CH2COOH) = 2n(CH3CH2COOK) =1.4 mol
M(CH3CH2COOK) = 112 g/mol
m(CH3CH2COOK) = n*M = 1.4 * 112 = 156.8 g
ответ 156.8 гр
Объяснение: