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salah1902
@salah1902
November 2021
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Какую работу совершит тело мощностью 3 квт за 2 мин
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dfkth
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A=Pt A=3000*120=360 000 Дж=360 кДж
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A=Pt A=3000*120=360 000 Дж=360 кДж