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obozina79
@obozina79
September 2021
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Камень свободно падает без начальной скорости. За какое время онтпролетит третий метр своего пути?
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sokolovvovikn
Verified answer
H1=2м h2=3 м h2-h1=1 м
t1=sqrt(2*h1/g)=sqrt(2*2*/10)=0,632 c
t2=sqrt(2*h2/g)=sqrt(2*3/10)=0,775 c
t=t2-t1=0,775-0,632=0,143 c
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Verified answer
H1=2м h2=3 м h2-h1=1 мt1=sqrt(2*h1/g)=sqrt(2*2*/10)=0,632 c
t2=sqrt(2*h2/g)=sqrt(2*3/10)=0,775 c
t=t2-t1=0,775-0,632=0,143 c