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ajiqu
@ajiqu
July 2022
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сколько бензина надо сжечь, чтобы превратить 200 г воды, взятой при температуре кипения? (L=2,3*10^6 дж/кг, q=46*10^6 дж/кг)
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axilles5157
Qбенз=q*mбенз
Qв=L*mв
Qб=Qв
q*mб=L*mв
mб= L*mв/q
mб=2300000Дж/кг*0,2кг/46000000Дж/кг=0,01кг=10г
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Qв=L*mв
Qб=Qв
q*mб=L*mв
mб= L*mв/q
mб=2300000Дж/кг*0,2кг/46000000Дж/кг=0,01кг=10г