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LORD86
@LORD86
October 2021
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Чему равна скорость пули массой 12 г, если при выстреле сгорает 2,4 г пороха? Удельная теплота сгорания пороха 38*10^5 Дж/кг.
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sokolovvovikn
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По закону сохранения энергии q*m1=m2*V^2/2
V=sqrt(2*q*m1/m2)=sqrt(2*38*10^5*2,4*10^-3/12*10^-3)=1230 м/с
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По закону сохранения энергии q*m1=m2*V^2/2V=sqrt(2*q*m1/m2)=sqrt(2*38*10^5*2,4*10^-3/12*10^-3)=1230 м/с