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fbcg20
@fbcg20
August 2022
1
3
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p=4200Дж/кг*°C
m=1.5кг
t1=20°C
t2=40°C
t=480 сек.
найти мощность тока
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Panovson
1)Q=cm(t2-t1) = 4200Дж(кг*К) * 1.5кг*(40°C-
20°C) = 126000Дж
2)P=Q/t = 126000Дж/600с = 210Вт.
1 votes
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Answers & Comments
2)P=Q/t = 126000Дж/600с = 210Вт.