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DjBukus
@DjBukus
August 2022
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Сколько воды можно нагреть от 0 град до 100 град сообщив ей 1200 дж теплоты? Удельная теплоёмкость воды 4200 дж/кг*град
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MashaPutnaj
Verified answer
Дано t1=0C t2=100C Q=1200 Дж m- ?
Q=c*m*(t2-t1)
m=Q/c*(t2-t1)=1200/4200*100=2,857*10^-3 кг=2,857 г
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Verified answer
Дано t1=0C t2=100C Q=1200 Дж m- ?Q=c*m*(t2-t1)
m=Q/c*(t2-t1)=1200/4200*100=2,857*10^-3 кг=2,857 г