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karolina1978
@karolina1978
July 2022
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Количество атомов водорода в сернистой кислоте количеством
вещества 10 моль равно
А) 1,204⋅10^23
Б) 3,01⋅10^23
В) 6,02⋅10^23
Г) 1,204⋅10^25
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linka1malinka
N=10 мольn=N/NaN=Na*nn=(6,02*10^23)*10
2 votes
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