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ana0stacy
@ana0stacy
July 2022
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КОМБИНАТОРИКА
Сколькими способами можно выбрать 3 книги, если на полке по 10 экземпляров семи различных учебников?
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АДИНКА2005
10!/(10-7)! = 10!/3! = 4*5*6*7*8*9*10 = 604800
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Answers & Comments
10!/(10-7)! = 10!/3! = 4*5*6*7*8*9*10 = 604800