Ответ:
№4 на фото
Объяснение:
№1
(а–3)(а–7)–2а(3а–5)=а²–7а–3а+21–6а²+10а= –5а²+21
№2
1–64b²=(1–8b)(1+8b)
№3
3x²+8x–3=3х²+3х+5х–3=3х²+5х+3х–3=х(3х+5)+3(х–1)=
=(3х+5)(х–1)(х+3)
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Answers & Comments
Ответ:
№4 на фото
Объяснение:
№1
(а–3)(а–7)–2а(3а–5)=а²–7а–3а+21–6а²+10а= –5а²+21
№2
1–64b²=(1–8b)(1+8b)
№3
3x²+8x–3=3х²+3х+5х–3=3х²+5х+3х–3=х(3х+5)+3(х–1)=
=(3х+5)(х–1)(х+3)