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anjuta5858
@anjuta5858
July 2022
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Конус.Площадь боковой поверхности 260пи и площадь полной поверхности 360пи, найдите радиус, высоту ,образующую
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potapov19461
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S(осн) =πR² = 360π-260π = 100π⇒R²=100, R=10.
S(бок) = πRL =π*10*L = 260π⇒L=26.
H=√(L²-R²)=√(26²-10²) = 24.
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Answers & Comments
Verified answer
S(осн) =πR² = 360π-260π = 100π⇒R²=100, R=10.S(бок) = πRL =π*10*L = 260π⇒L=26.
H=√(L²-R²)=√(26²-10²) = 24.