Home
О нас
Products
Services
Регистрация
Войти
Поиск
kavai697
@kavai697
June 2022
1
9
Report
Корень из 4-x^2 * (sin^7x-cos^7x)=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
dimanevedimka
√4x² × (sin²7x-cos²7x)=0
√4x² =0 |или| sin²7x-cos²7x=0
x=0; -(cos²7x- sin²7x)=0
cos²7x- sin²7x = cos14x
cos14x=0
14x=π/2+πn
x=π/28+πn/14, n∈Z
Ответ: x=0, x=π/28+πn/14, n∈Z;
1 votes
Thanks 0
kavai697
4-x^2
kavai697
во втором 7 это степень, а не аргумент
dimanevedimka
тогда x=+-2
dimanevedimka
x=pi/2+pin тогда во втором множителе
kavai697
мне то решение нужно
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Корень из 4-x^2 * (sin^7x-cos^7x)=0..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
√4x² =0 |или| sin²7x-cos²7x=0
x=0; -(cos²7x- sin²7x)=0
cos²7x- sin²7x = cos14x
cos14x=0
14x=π/2+πn
x=π/28+πn/14, n∈Z
Ответ: x=0, x=π/28+πn/14, n∈Z;