Home
О нас
Products
Services
Регистрация
Войти
Поиск
vikamolchanova1
@vikamolchanova1
August 2022
1
10
Report
корень из cos2x -cosx=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
√cos2x-cosx=0
√cos2x=cosx
cosx≥0⇒x∈([-π/2+2πk;π/2+2πk,k∈z
возведем в квадрат
cos2x=cos²x
2cos²x-1-cos²x=0
cos²x-1=0
cos²x=1
cosx=-1⇒x=π+2πk,k∈z не удов усл
cosx=1⇒x=2πk,k∈z
1 votes
Thanks 3
More Questions From This User
See All
vikamolchanova1
August 2022 | 0 Ответы
ya treugolnike avs av8 sm vs10 sm as13 smm seredina avk seredina vsnajt
Answer
vikamolchanova1
July 2022 | 0 Ответы
h2322c1b3f1dc381d8dcfe4f56c84c25a6 48040
Answer
vikamolchanova1
July 2022 | 0 Ответы
2 lthlt2p
Answer
vikamolchanova1
July 2022 | 0 Ответы
v share na rasstoyanii 12 sm vid jogo centra provedeno sechenie ploshad kotorogo 64
Answer
vikamolchanova1
July 2022 | 0 Ответы
ochen srochno ploshad pryamougolnoj trapecii ravna 32 kornya iz 3 a ostryj ugol 6
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "корень из cos2x -cosx=0..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
√cos2x=cosx
cosx≥0⇒x∈([-π/2+2πk;π/2+2πk,k∈z
возведем в квадрат
cos2x=cos²x
2cos²x-1-cos²x=0
cos²x-1=0
cos²x=1
cosx=-1⇒x=π+2πk,k∈z не удов усл
cosx=1⇒x=2πk,k∈z