Ответ:
1.63 i 2.76 sootvetstcenno
Объяснение:
lambda1 = 0.76 mkm
lambda2 = 0.48 mkm
E_1 = hc/lambda1 = 6.62 * 10^(-34) * 3 *10^8/0.76 10^(-6)=26.1 * 10^(-20) joul = 1.63 eV
E_2 = hc/lambda2 = 6.62 * 10^(-34) * 3 *10^8/0.45 10^(-6)= 44.1 * 10^(-20) joul = 2.76 eV
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Ответ:
1.63 i 2.76 sootvetstcenno
Объяснение:
lambda1 = 0.76 mkm
lambda2 = 0.48 mkm
E_1 = hc/lambda1 = 6.62 * 10^(-34) * 3 *10^8/0.76 10^(-6)=26.1 * 10^(-20) joul = 1.63 eV
E_2 = hc/lambda2 = 6.62 * 10^(-34) * 3 *10^8/0.45 10^(-6)= 44.1 * 10^(-20) joul = 2.76 eV