BaCl2*XH2O

пусть m(BaCl2*xH2O)=100г; m(H2O)=14,8г;n(H2O)=14,8:18=0,8моль; m(BaCl2)=85,2г;

n(BaCl2)=85,2:208=0,4моль;

                                                        n(BaCl2):n(H2O)=0,4:0,8

                                                                                       1:2

                                      ответ:BaCl2*2H2O