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ScarlettDark
@ScarlettDark
August 2022
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Кто-нибудь может помочь сделать?
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hlopushinairina
(2sin²α/2 -1)/(cos²α/2 -sin²α/)=-cosα/cosα=-1;
используемые формулы:
cos2α=cos²α-sin²α;
cos2α=1-2sin²α;
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Answers & Comments
используемые формулы:
cos2α=cos²α-sin²α;
cos2α=1-2sin²α;