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shinaev2013
@shinaev2013
July 2022
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Кто сможет решить? Математика
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187187187
X=4sin(п/3-п/3*t)
V=x'=4*(-п/3)*cos(п/3-п/3*t)=
-4п/3*cos(п/3-п/3*t)
A=V'=-4п/3*(-п/3)*(-sin(п/3-п/3*t))=
- 4п^2/9*sin(п/3-п/3*t)
A(t=2)=-4п^2/9*sin(п/3-2п/3)=
4п^2/9*sin(п/3)=
(4п^2*¥3)/(2*9)= (2п^2*¥3)/9
¥это корень
2 votes
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Answers & Comments
V=x'=4*(-п/3)*cos(п/3-п/3*t)=
-4п/3*cos(п/3-п/3*t)
A=V'=-4п/3*(-п/3)*(-sin(п/3-п/3*t))=
- 4п^2/9*sin(п/3-п/3*t)
A(t=2)=-4п^2/9*sin(п/3-2п/3)=
4п^2/9*sin(п/3)=
(4п^2*¥3)/(2*9)= (2п^2*¥3)/9
¥это корень