ph=14-poh
ph=14-(-lg(10^-1))=14-1=13
pKa=-lg(Ka)=-lg(1.8*10^-5)=4.8
100/(1+10^(13-4.8)=6.3*10^-7%
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ph=14-poh
ph=14-(-lg(10^-1))=14-1=13
pKa=-lg(Ka)=-lg(1.8*10^-5)=4.8
100/(1+10^(13-4.8)=6.3*10^-7%