[H+] = 10–5, получим:
pH = – lg10–5 = – (– 5 lg10) = 5.
[Н+][ОН–] = 10–14
рОН=14-5=9
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[H+] = 10–5, получим:
pH = – lg10–5 = – (– 5 lg10) = 5.
[Н+][ОН–] = 10–14
рОН=14-5=9