lg40-lg2=lg(10-2x); ОДЗ: 10-2x>0; х<5
lg (40:2) = lg(10-2x)
20 = 10-2х
10 = -2х
х= -5
ответ: х = -5
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lg40-lg2=lg(10-2x); ОДЗ: 10-2x>0; х<5
lg (40:2) = lg(10-2x)
20 = 10-2х
10 = -2х
х= -5
ответ: х = -5