Home
О нас
Products
Services
Регистрация
Войти
Поиск
kamikadze2000
@kamikadze2000
July 2022
1
4
Report
Литр озона весит при нормальных условиях 2,143 г. Определите молекулярный вес озона и его плотность по воздуху.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Alexei78
Дано
V(O3) = 1 L = 1000 mL
m(O3) = 2.143 g
-------------------------
M(O3)-?
D(возд) -?
M(O3) = m(O3)*Vm / V(O3) = 2.143 * 22.4 / 1 = 48 g/mol , Vm = 22.4 L/mol
D(возд) = M(O3) / 29 = 48 / 29 = 1.655
ответ 48 г/моль, 1.655
1 votes
Thanks 2
More Questions From This User
See All
kamikadze2000
August 2022 | 0 Ответы
come...
Answer
kamikadze2000
August 2022 | 0 Ответы
help stati zakonov otnosyatsya k oficialnomu stilyu ili publicisticheskomu stilyu
Answer
kamikadze2000
August 2022 | 0 Ответы
70 ballov napisat dushevnoe esse na temu rodina dlya menya pliz nelzya s i
Answer
kamikadze2000
July 2022 | 0 Ответы
pomogite korotko napisat o chem tekst dayu 30 ballovtekst nebolshoj delo v to
Answer
kamikadze2000
July 2022 | 0 Ответы
opishite kartinu chto delayut lyudi8f37a35ae2918ee0b7aedd50bc922db1 12122
Answer
kamikadze2000
July 2022 | 0 Ответы
opishite kartinu chto delayut lyudi
Answer
kamikadze2000
July 2022 | 0 Ответы
smotrite na kartinu chto delayut lyudi
Answer
kamikadze2000
July 2022 | 0 Ответы
kuda ischez dzhon kak dumaete chto s nim sluchilos
Answer
kamikadze2000
July 2022 | 0 Ответы
help dayu 40 ballov angl
Answer
kamikadze2000
July 2022 | 0 Ответы
pomogite 40 ballov dayu9b89a823d1a4d0e7623f0f440ac133b8 73914
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Литр озона весит при нормальных условиях 2,143 г. Определите молекулярный вес оз..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
V(O3) = 1 L = 1000 mL
m(O3) = 2.143 g
-------------------------
M(O3)-?
D(возд) -?
M(O3) = m(O3)*Vm / V(O3) = 2.143 * 22.4 / 1 = 48 g/mol , Vm = 22.4 L/mol
D(возд) = M(O3) / 29 = 48 / 29 = 1.655
ответ 48 г/моль, 1.655