Ответ:
log [0,1] (7x + 3) > -1
ОДЗ: x > -3/7
7x + 3 < 0,1^-1
7x + 3 < 10
7x < 7
x < 1, x > -3/7
x є (-3/7, 1)
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Ответ:
log [0,1] (7x + 3) > -1
ОДЗ: x > -3/7
7x + 3 < 0,1^-1
7x + 3 < 10
7x < 7
x < 1, x > -3/7
x є (-3/7, 1)