log √2 (x^2+10x)>= log √2 (x-14) Решить неравенство. Created by deanonm. algebra-ru

log √2 (x^2+10x)>= log √2 (x-14) Решить неравенство...

deanonm @deanonm

July 2022 1 7 Report

log √2 (x^2+10x)>= log √2 (x-14)
Решить неравенство

Answers & Comments

m11m

Verified answer

ОДЗ:
1) x² +10x>0
x(x+10)>0
x=0 x= -10
+ - +
----------- -10 ------------- 0 ------------
\\\\\\\\\\\\\ \\\\\\\\\\\\\
x∈(-∞; -10)U(0; +∞)

2) x-14>0
x>14
В итоге ОДЗ: х∈(14; +∞)

Так как основание логарифма √2>0, то
x²+10x≥x-14
x²+10x-x+14≥0
x²+9x+14≥0
x²+9x+14=0
D=9² -4*14=81-56=25
x₁=(-9-5)/2= -7
x₂=(-9+5)/2= -2
+ - +
----------- -7 -------------- -2 -------------
\\\\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\
x∈(-∞; -7]U[-2; +∞)

С учетом ОДЗ получаем
х∈(14; +∞)
Ответ: (14; +∞)

5 votes Thanks 4

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