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1903200019
@1903200019
August 2022
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Логарифмы...Упростите выражения lg b/lg a + 2/log b a -log a b^3=
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sedinalana
Verified answer
Lgb/lga+log(b)b²/log(b)a-log(a)b³=log(a)b+log(a)b²-log(a)b³=
=log(a)(b*b²/b³)=log(a)1=0
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Answers & Comments
Verified answer
Lgb/lga+log(b)b²/log(b)a-log(a)b³=log(a)b+log(a)b²-log(a)b³==log(a)(b*b²/b³)=log(a)1=0