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rebrovavlada
@rebrovavlada
July 2022
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log по основанию 2 (x^2-3x-10)=3
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MizoriesKun
Verified answer
ОДЗ х²-3х-10>0
D=9+40=49 √D=7
x=(3+7)/2=5
x=(3-7)/2=-2
x∈(-∞;-2)∪(5;+∞)
х²-3х-10=2³
х²-3х-10= 8
х²-3х-10-8=0
х²-3х-18=0
D=9+72=81 √D=9
x₁=
(3+9)/2=
6
x₂=
(3-9)/2=
-3
оба корня подходят под ОДЗ
6²-3*6-10=36-18-10=8
(-3)²-3*(-3)-10=9+9-10=8
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Answers & Comments
Verified answer
ОДЗ х²-3х-10>0
D=9+40=49 √D=7
x=(3+7)/2=5
x=(3-7)/2=-2
x∈(-∞;-2)∪(5;+∞)
х²-3х-10=2³
х²-3х-10= 8
х²-3х-10-8=0
х²-3х-18=0
D=9+72=81 √D=9
x₁=(3+9)/2=6
x₂=(3-9)/2=-3
оба корня подходят под ОДЗ
6²-3*6-10=36-18-10=8
(-3)²-3*(-3)-10=9+9-10=8