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toriblinova
@toriblinova
July 2022
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log по основанию √3(x^2-3x-7)=2
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тто
Смотри фото)))))))))))))))))))))
1 votes
Thanks 0
vaash
X^2 -3x-7 = ( sqrt(3) )^2 = 3;
x^2 -3x-10 = 0;
x^2 -5x + 2x-10 = 0;
x(x-5)+2(x-5) = 0;
(x+2)(x-5) = 0;
x = -2 или x = 5;
ответ: -2; 5
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Answers & Comments
x^2 -3x-10 = 0;
x^2 -5x + 2x-10 = 0;
x(x-5)+2(x-5) = 0;
(x+2)(x-5) = 0;
x = -2 или x = 5;
ответ: -2; 5