log Помогите плииииииииз!. Created by Bolatzhan. algebra-ru

log Помогите плииииииииз!...

Bolatzhan @Bolatzhan

July 2022 2 4 Report

log Помогите плииииииииз!

sedinalana

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X>0
log(3)x=a
a²-3a+2=0
a1+a2=3 U a1*a2=2
a1=1⇒log(3)x=1⇒x=3
a2=2⇒log(3)x=2⇒x=9

1 votes Thanks 1

ShirokovP

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Путь log3(x) = t
тогда получим квадратное уравнение:
t^2 - 3t + 2 = 0

D = 9 - 8 = 1

t1 = (3 + 1)/2 = 4/2 = 2;
t2 = (3 - 1)/2 = 2/2 = 1

log3(x) = 2
x = 9

log3(x) = 1
x = 3^(1)
x = 3

Ответ
9; 3

2 votes Thanks 1

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