Home
О нас
Products
Services
Регистрация
Войти
Поиск
antonovaalla98
@antonovaalla98
August 2022
1
9
Report
log² ₓ₊₂(x-18)²+32 <= 16logₓ₊₂(36+16x-x²)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
ОДЗ
x+2⇒x>-2
x+2≠1⇒x≠-1
x²-16x-36<0⇒-2<x<18
x1+x2=16 U x1*x2=-36⇒x1=-2 U x2=18
x∈(-2;-1) U (-1;18)
4log²(x+2)(x-18)+32-16log(x+2)(x+2)-16log(x+2)(x-18)≤0
4log²(x+2)(x-18)+32-16-16log(x+2)(x-18)≤0
4log²(x+2)(x-18)-16-16log(x+2)(x-18)≤0
log(x+2)(x-18)=a
4x²-16x+16≤0
x²-4x+4≤0
(x-2)²≤0
x=2
1 votes
Thanks 1
antonovaalla98
После замены на a идет неравенство с x, это же мы a нашли, это не ответ
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "log² ₓ₊₂(x-18)²+32 <= 16logₓ₊₂(36+16x-x²)..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
ОДЗx+2⇒x>-2
x+2≠1⇒x≠-1
x²-16x-36<0⇒-2<x<18
x1+x2=16 U x1*x2=-36⇒x1=-2 U x2=18
x∈(-2;-1) U (-1;18)
4log²(x+2)(x-18)+32-16log(x+2)(x+2)-16log(x+2)(x-18)≤0
4log²(x+2)(x-18)+32-16-16log(x+2)(x-18)≤0
4log²(x+2)(x-18)-16-16log(x+2)(x-18)≤0
log(x+2)(x-18)=a
4x²-16x+16≤0
x²-4x+4≤0
(x-2)²≤0
x=2